User talk:Cryptanalysis

From Wikipedia, the free encyclopedia

a⁽a^a) = b
(a^a)loga = logb
(a^a) = logb / loga
aloga = log(logb / loga)
aloga = log(logb) − log(loga)
a = (log(logb) − log(loga)) / loga

a⁽a^a) = b
(a^a)loga = logb
(a^a) = logb / loga
a = (logb / loga)⁽1 / a)

(logb / loga)⁽1 / a) = (log(logb) − log(loga)) / loga
--Cryptanalysis 06:49, 16 February 2006 (UTC)