User:Cryptanalysis

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$a (a a) = b$
$(a a) l o g a = l o g b$
$(a a) = l o g b / l o g a$
$a l o g a = l o g (l o g b / l o g a)$
$a l o g a = l o g (l o g b) - l o g (l o g a)$
$a = (l o g (l o g b) - l o g (l o g a)) / l o g a$

$a (a a) = b$
$(a a) l o g a = l o g b$
$(a a) = l o g b / l o g a$
$a = (l o g b / l o g a) (1 / a)$

$(l o g b / l o g a) (1 / a) = (l o g (l o g b) - l o g (l o g a)) / l o g a$
--Cryptanalysis 06:49, 16 February 2006 (UTC) $\left \Vert \left ( \frac{dr}{du} \times \frac{dr}{dv} \right ) \right \|$ $\iint_{S} \,F \dot n\,dS$ $\int_{0}^{42} \, du = 42$ $\sum_{n=0}^p\frac{m^2\,n} {3^m\left(m\,3^n+n\,3^m\right)}$