User:Cpl.Luke

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\oint_C \mathbf{B} \cdot d\mathbf{l} = \mu_0 I_{\mathrm{encl}} + \mu_0 \epsilon_0 \frac{d \mathbf{\Phi_E}}{dt}  
\oint_C \mathbf{E} \cdot d\mathbf{A} = \frac{Q_{enc}}{\epsilon_0}
\oint_C \mathbf{B} \cdot d\mathbf{A} = 0
 \mathbf{V} = - \frac{d\mathbf{\Phi_B}}{dt}
thats you


"Mmm, one does have to learn to look at art, just as you must know French to read a story printed in French. But in general it's up to the artist to use language that can be understood, not hide it in some private code like Pepys and his diary. Most of these jokers don't even want to use language you and I know or can learn . . . they would rather sneer at us and be smug, because we 'fail' to see what they are driving at. If indeed they are driving at anything--obscurtiy is usually the refuge of incompetence." -jubal harshaw, pg. 400, stranger in a strange land (uncut version), Robert A. Heinlein