Talk:Ceva's theorem

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[edit] Popular how?

In what way could this theorem be construed to be "popular" among schoolchildren?  :)

I popped in to ask much the same question...perhaps they're defining "schoolchildren" to be "high school and college students who are fanatically interested in geometry" Kaz 01:15, 5 Feb 2005 (UTC)
I think it's a) popular to teach it b) has been frequently examined historically. Mr. Jones 10:50, 5 May 2005 (UTC)

[edit] Errors ?

There are many errors in this article in case 2 (D or E or F not on the line segments)

  1. The egality is also true if (AD), (BE), (CF) are parallel
  2. To proove that the line are concurrent or parallel, the egality must be writen with measurements of line segments that are allowed negative values. So the proof is'nt valable.
  3. \frac{AF '}{F 'B}=\frac{AF}{FB} ==> F=F' or F and F' are harmonic division of [AB]

I can't modify this article because I'm french and I can't write in english. HB on fr 7 August 2007 (UTC)

[edit] 2 cases

As I see it, the proof doesn't split into 2 cases, yet the pictures suggest so. —Preceding unsigned comment added by Richard Molnár-Szipai (talk • contribs) 14:39, 11 March 2008 (UTC)