Borough of Sebastopol
From Wikipedia, the free encyclopedia
| Borough of Sebastopol Victoria |
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| Image:Old lgadot Sebastopol.png Location in Victoria |
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| Population: | 7800 (1992)[1] |
| Established: | 1864 |
| Area: | 7.61 km² (2.9 sq mi) |
| Council Seat: | Sebastopol |
| County: | Grenville |
The Borough of Sebastopol was a Local Government Area located about 4 kilometres (2 mi) south of the regional city of Ballarat, Victoria, Australia. The borough covered an area of 7.61 square kilometres (2.9 sq mi), and existed from 1864 until 1994.
Sebastopol was first incorporated as a borough on 1 October 1864.[2] On 6 May 1994, it was abolished, and merged with City of Ballaarat, Shire of Ballarat and parts of the Shires of Bungaree, Buninyong, Grenville and Ripon into the City of Ballarat.[3]
[edit] Population
| Year | Population |
|---|---|
| 1954 | 3,265 |
| 1958 | 3,480* |
| 1961 | 4,663 |
| 1966 | 4,966 |
| 1971 | 5,268 |
| 1976 | 5,941 |
| 1981 | 6,462 |
| 1986 | 7,011 |
| 1991 | 7,527 |
* Estimate in the 1958 Victorian Year Book.
[edit] References
- ^ Australian Bureau of Statistics, Victoria Office (1994). Victorian Year Book, 49-52. ISSN 0067-1223.
- ^ (1992) Victorian Municipal Directory. Brunswick: Arnall & Jackson. Accessed at State Library of Victoria, La Trobe Reading Room.
- ^ Australian Bureau of Statistics (1 August 1995). Victorian local government amalgamations 1994-1995: Changes to the Australian Standard Geographical Classification. Commonwealth of Australia. ISBN 0-642-23117-6. Retrieved on 2008-01-05.
