Benton Township, Elkhart County, Indiana
From Wikipedia, the free encyclopedia
Benton Township | |
Location of Benton Township in Elkhart County | |
Coordinates: | |
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Country | United States |
State | Indiana |
County | Elkhart |
Area | |
- Total | 35.9 sq mi (92.97 km²) |
- Land | 35.84 sq mi (92.84 km²) |
- Water | 0.05 sq mi (0.14 km²) |
Elevation [1] | 853 ft (260 m) |
Population (2000) | |
- Total | 2,342 |
- Density | 65.34/sq mi (25.23/km²) |
FIPS code | 18-04798[2] |
GNIS feature ID | 453105 |
Benton Township is one of sixteen townships in Elkhart County, Indiana. As of the 2000 census, its population was 2,342.
Contents |
[edit] Geography
Benton Township covers an area of 35.9 square miles; 0.05 square miles (0.14 percent) of this is water.
[edit] Cities and towns
- Millersburg (south quarter)
[edit] Unincorporated towns
[edit] Adjacent townships
- Clinton Township (north)
- Eden Township, LaGrange County (northeast)
- Perry Township, Noble County (east)
- Sparta Township, Noble County (southeast)
- Turkey Creek Township, Kosciusko County (south)
- Van Buren Township, Kosciusko County (southwest)
- Jackson Township (west)
- Elkhart Township (northwest)
[edit] Major highways
[edit] Cemeteries
The township contains two cemeteries: Brown and Hire.
[edit] References
- ^ US Board on Geographic Names. United States Geological Survey (2007-10-25). Retrieved on 2008-01-31.
- ^ American FactFinder. United States Census Bureau. Retrieved on 2008-01-31.
[edit] External links
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