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Joseph Stevenson May 27, 2008
The Specific Heat of a Metal Lab
Data and Observations:
Measurements of Mass and Temperature: Trial 1 Trial2 (given) Mass of lead shot 91.80 g 106.08 g Initial temperature of water in cup 23.1 oC 23.2 oC Initial temperature of lead shot (temperature of boiling water) 98.9 oC 99.24 oC Maximum temperature of lead + water 26.1 oC 95.47 oC Mass of water 100.01 g 100 g
Analysis and Conclusions:
1. Determine the changes in temperature of the water (Twater) and of the lead shot (Tlead) for each trial.
Trial 1:
mlead x Clead x Tlead = mwater x Cwater x Twater
91.8 g x 0.1276 J x (98.9 - Tfinal) oC = 100.1 g x 4.18 J x (Tfinal – 23.1) oC
g x oC g x oC
11.71368 (98.9 - Tfinal) = 418.418 (Tfinal – 23.1)
1158.482952 - 11.71368Tfinal = 418.418Tfinal – 9665.4558
430.13168Tfinal = 10823.93875
Tfinal = 25.16424447
Trial 2:
mlead x Clead x Tlead = mwater x Cwater x Twater
106.08 g x 0.1276 J x (99.24 - Tfinal) oC = 100 g x 4.18 J x (Tfinal – 23.2) oC
g x oC g x oC
13.535808 (99.24 - Tfinal) = 418 (Tfinal – 23.2)
1343.293586– 13.535808Tfinal = 418 Tfinal – 9697.6
431.535808Tfinal = 11040.89359
Tfinal = 25.58511573
2. Calculate the heat gained by the water in each trial.
Trial 1:
mwater x Cwater x Twater = Heat gained by water
100.1 g x 4.18 J x (25.16424447 – 23.1) oC = Heat gained by water
g x oC
418.418 (2.06424447) J = Heat gained by water
863.7170426 J = Heat gained by water
Trial 2:
mwater x Cwater x Twater = Heat gained by water
100 g x 4.18 J x (25.58511573 – 23.2) oC = Heat gained by water
g x oC
418 (2.38511573) J = Heat gained by water
996.9783751 J = Heat gained by water
3. Remembering that the heat gained by the water equals the heat lost by the lead, calculate the specific heat of lead for each trial.
Trial 1:
Heat lost = Clead
Mlead x Tlead
863.7170426J = Clead 91.80 g x (98.9 - 25.16424447) oC
863.7170426 J = Clead 91.80 g x (73.7358) oC
863.7170426 J = Clead 6768.9846 g x oC
0.1276 J = Clead g x oC
Trial 2:
Heat lost = Clead
Mlead x Tlead
996.9783751 J = Clead 106.08 g x (99.24 - 25.58511573) oC
996.9783751 J = Clead 106.08 g x 73.6549oC
996.9783751 J = Clead 7813.3118 g x oC
0.1276 J = Clead g x oC
