Battle of Donkey Island
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Battle of Donkey Island | |||||||
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Part of the Post-invasion Iraq | |||||||
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Belligerents | |||||||
United States | Al-Qaeda in Iraq | ||||||
Strength | |||||||
30 - 50 soldiers | 40 - 70 fighters | ||||||
Casualties and losses | |||||||
2 KIA 11WIA |
32 KIA |
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The Battle of Donkey Island was a skirmish that occurred on 30 June 2007 between elements of the U.S. Task Force 1-77 Armor Regiment, the 2nd Battalion 5th Marines and a numerically superior force of Al-Qaeda in Iraq insurgents outside the city of Ramadi in the Al-Anbar province in Iraq.[1][2]
Official reports indicate that the US suffered 2 dead and 11 wounded soldiers in the conflict while an estimated 32 insurgents were killed (out of an estimated force of 40 - 70 fighters). In military terms, the battle was a complete victory for the U.S. forces, detecting and annihilating an insurgent force before it could launch a planned assault on Ramadi. Politically, the action revealed the continuing ability of Al-Qaeda in Iraq to plan and assemble forces in their attempt to destabilize the Anbar region.
[edit] Timeline of Events
On the night of June 30, 2007, a routine patrol on the outskirts of Ramadi revealed the presence of a company-sized force of insurgents. Partially hidden behind two trucks, the insurgent force began firing on the reconnaissance group, forcing them to retreat to nearby cover.
After a firefight in the moon-lit night, a near-by platoon arrived to reinforce the US side. Although outnumbered, the Americans brought superior firepower to bear and eventually began to shift the tide of battle.