User:Arperry

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User page = sandbox? Here, the answer is Yes.

[edit] Maths

d = \frac{1+min(\frac{S}{P},2)}{2}P

d' = \frac{2A_2}{A_1+1} d \ | \ A_1 > A_2

 %Cr = \frac{A_1}{A_1 + CC}

m' = m + \frac{I}{5}