Talk:Area

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Geometry guy 17:49, 14 April 2007 (UTC)

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	The following comments have been left for this page: Geometry guy 17:49, 14 April 2007 (UTC) (edit)

1 Headline text
2 problems in electrical wire table
3 Surface area
4 The Areas
5 Formulas Table
6 Merge area and surface area
7 SQUARE AREA
8 Import from Surface area
9 yall

[edit] Headline text

99% of references ti area are about sizes of countries and planets, so I put part of it in area (geometry), (I will make changes in math part of refs). Tosha

hmmm, well there are a few errors but most recognisable is the - or "minus" before each number. Please note that the - key is a minus not a mear explanation line and there for numbers displayed as -10 cand easily be confused for the actual minus 10 number, not just postive 10.

[edit] problems in electrical wire table

The numbers for area and diameter do not agree.
The purpose and use of the table should be explained.
Does this really belong here, or is there a better place for it?

Gene Nygaard 17:37, 27 Dec 2004 (UTC)

[edit] Surface area

Surface area could definently use it's own article. ike9898 01:09, Feb 16, 2005 (UTC)

Well, when you've written enough about it so that this article becomes unweildy, and enough to make a distinguishable article here, then maybe we can look into that. Gene Nygaard 01:41, 16 Feb 2005 (UTC)

Surface area of a sphere??--Jaysscholar 21:45, 25 September 2005 (UTC)

[edit] The Areas

Hi. This article is good but needs a few changes. The derivation of the areas are not explained and neither are there any diagrams. It's not user friendly! Plus, there could also be some sums and more information on areas of prisms, pyramids etc.. When I saw this there were only two formulas for the areas under "some useful formulae" , So I've added some more.---Pujita

[edit] Formulas Table

i've alphabetized this table, and took out all the "A"s and "An"s. it seems more user-friendly now. who ever wrote that thing above is such a dork and geek!!!!! lol. —Preceding unsigned comment added by 69.132.81.114 (talk) 22:42, 7 October 2007 (UTC)

also, since most human beings looking for the formula for the area of a circle will be looking for "circle", i put a note in the table directing them to see the formula for "disk".

--Brianbarney 02:05, 19 July 2006 (UTC)

I'd rather see this in the old form where the rows are ordered according to complexity as is most common. The table only has eleven entries and does not need to be alphabetized to be useful. I strongly feel that it was better the other way!

As for the circle entry, a circle is not a synonym for a disk. --Swift 10:19, 19 July 2006 (UTC)

i accept the veto. but maybe you can explain why the area of an enclosed circle has a special name, yet the areas of an enclosed square or triangle do not... as far as i know.

--Brianbarney 07:44, 14 August 2006 (UTC)

Thanks. I'm not aware of any other name for the area enclosed square, triangle etc. either.

I cannot, unfortunately, offer any better explanation than that there may simply be a greater need in the English language for a word representing the concept of a disk than the areas of other shapes.

If in need to distinguish the two, you can always result to using square, triangular, etc. -area. --Swift 00:38, 15 August 2006 (UTC)

[edit] Merge area and surface area

Admittedly area can apply to non-surfaces, but there is no need to have two articles. One begins with area and the other has surface area on the second line. There is no need for this repetition. Richard001 09:47, 1 August 2007 (UTC)

We have area (geometry) as well... can we not just roll them into one? It's mainly a mathematical concept, so it would be difficult to make an article than merely summarizes the geometry article. Richard001 10:09, 1 August 2007 (UTC)

I oppose merging surface area here. Surface area is a concept in solid (3d) geometry, which makes it distinct enough from the concept of area in plane (2d) geometry to rate its own article. Argyriou (talk) 18:33, 26 September 2007 (UTC)

[edit] SQUARE AREA

I appreciate that geometry can be very complicated, however my question, is simplistic to the extreme. The question relates to the calculation of Square Area within different Shapes where Perimeter Lengths are equal.

Logic asks, should different Shapes, which have the same Perimeter length, not have the same Area within them? This shows the logic under question: a Square with Perimeter 16 units a Circle with Circumference 16 units a Triangle with Perimeter 16 units a Parallelogram with Perimeter 16 units any Shape where Perimeter is 16 units

Although all of the Shapes are different, each of their Perimeter lengths are the same and would form a 4x4 Square Perimeter. We know that the SqRt of Perimeter length when Squared is the SQ. Area within the Perimeter. So why are the various formulae necessary to calculate Area? Why do the various formulae produce a result that disagrees with this basic logic?

Can someone explain this? --Layman1 (talk) 11:26, 11 December 2007 (UTC)

[edit] Import from Surface area

I am not sure how to fit it in here, but the following table decidedly does not belong to "Surface area", where it was found. Arcfrk (talk) 08:19, 11 March 2008 (UTC)

Note: For 2D figures, the surface area and the area are the same.

Common equations for surface area (2-Dimensional Objects):
Shape	Equation	Variables
A rectangle:	$l \cdot w$	l = length, w = width
A circle:	$\pi \cdot r^2$	r = radius
Any regular polygon:	$P \cdot a/2$	P = length of the perimeter, a = length of the apothem of the polygon (the distance from the center of the polygon to the center of one side)
A parallelogram:	$B \cdot h$	B (base) = any side, h (height) = the distance between the lines that the sides of length B lie on
A trapezoid:	$(B+b) \cdot h/2$	B and b = lengths of the parallel sides, h = distance between the lines on which the parallel sides lie
A triangle (1):	$B \cdot h/2$	B = any side, h = distance from the line on which B lies to the other point of the triangle
A triangle (2) (Heron's formula):	$\sqrt{[p \cdot (p-a) \cdot (p-b) \cdot (p-c)]}$	a, b and c = sides of triangle, p = half of the perimeter, or (a+b+c)/2