Talk:Adjoint representation

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Mathematics rating:	Start Class	High Priority	Field: Algebra
Please update this rating as the article progresses, or if the rating is inaccurate. Click to show/hide comments. Please add to or update the comments to suggest improvements to the article. Geometry guy 01:07, 15 June 2007 (UTC)

I really wouldn't say [Cayley's theorem] has much to do with it. There is no obvious relation, for a group G, between acting on itself by conjugation and by translation - very different permutation representations.

Charles Matthews 06:43, 23 Aug 2003 (UTC)

[edit] Any Lie group is a representation of itself?

This does not sound right. "representation" can refer either to a vector space with an action of a group or to the group morphism from G to GL(V). Neither of these applies here.

Better: any Lie group G acts on itself...