Zwingle, Iowa

From Wikipedia, the free encyclopedia

Zwingle is a city in Dubuque County, Iowa, United States. The population was 100 at the 2000 census.

[edit] Geography

Zwingle is located at 42°17′52″N, 90°41′13″W (42.297837, -90.687038)^GR1.

According to the United States Census Bureau, the city has a total area of 0.4 km² (0.2 mi²). None of the area is covered with water.

[edit] Demographics

As of the census^GR2 of 2000, there were 100 people, 42 households, and 23 families residing in the city. The population density was 241.3/km² (640.9/mi²). There were 43 housing units at an average density of 103.8/km² (275.6/mi²). The racial makeup of the city was 98.00% White, 1.00% Asian and 1.00% Pacific Islander. Hispanic or Latino of any race were 1.00% of the population.

There were 42 households out of which 31.0% had children under the age of 18 living with them, 45.2% were married couples living together, 9.5% had a female householder with no husband present, and 42.9% were non-families. 38.1% of all households were made up of individuals and 19.0% had someone living alone who was 65 years of age or older. The average household size was 2.38 and the average family size was 3.25.

In the city the population was spread out with 31.0% under the age of 18, 5.0% from 18 to 24, 28.0% from 25 to 44, 23.0% from 45 to 64, and 13.0% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 117.4 males. For every 100 females age 18 and over, there were 86.5 males.

The median income for a household in the city was $26,667, and the median income for a family was $45,625. Males had a median income of $25,417 versus $19,375 for females. The per capita income for the city was $18,916. There were no families and 1.4% of the population living below the poverty line, including no under eighteens and none of those over 64.