Zilwaukee Township, Michigan
From Wikipedia, the free encyclopedia
Zilwaukee Township is a civil township of Saginaw County in the U.S. state of Michigan. As of the 2000 census, the township population was 61. The city of Zilwaukee is in the southwest corner of the township, but is politically independent.
[edit] Geography
According to the United States Census Bureau, the township has a total area of 15.7 km² (6.1 mi²). 14.8 km² (5.7 mi²) of it is land and 0.9 km² (0.3 mi²) of it (5.45%) is water.
[edit] Demographics
As of the census2 of 2000, there were 61 people, 23 households, and 18 families residing in the township. The population density was 4.1/km² (10.6/mi²). There were 26 housing units at an average density of 1.8/km² (4.5/mi²). The racial makeup of the township was 90.16% White, and 9.84% African American.
There were 23 households out of which 26.1% had children under the age of 18 living with them, 73.9% were married couples living together, and 21.7% were non-families. 17.4% of all households were made up of individuals and none had someone living alone who was 65 years of age or older. The average household size was 2.65 and the average family size was 3.06.
In the township the population was spread out with 24.6% under the age of 18, 8.2% from 18 to 24, 16.4% from 25 to 44, 34.4% from 45 to 64, and 16.4% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 144.0 males. For every 100 females age 18 and over, there were 130.0 males.
The median income for a household in the township was $50,625, and the median income for a family was $52,188. Males had a median income of $50,938 versus $23,750 for females. The per capita income for the township was $21,268. None of the population and none of the families were below the poverty line.
