World Scrabble Championship 2005
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World Scrabble Championship 2005
Won by Adam Logan from 102 players
16th November 2005 - 20th November 2005
Held in London, England
Sponsored by Mattel
Contents |
[edit] Format
The World Scrabble Championship 2005 was held in the Marriott Regent's Park Hotel, London, England between 16 November and 20 November. As in previous years, the tournament began with a 24-round Swiss tournament over three days. The top two players from this phase contested a best-of-five final.
[edit] Results
The round robin stage involved 102 players, the largest number of players in WSC history.
The winner was Adam Logan of Canada, who beat Pakorn Nemitrmansuk of Thailand 3-0 in the final. Notably, Nemitrmansuk was also the beaten finalist at WSC 2003.
This was the fourth time in eight events that a Canadian had won, including one year in which a Canadian played for the United States.
[edit] Participants
Places were allocated by country. The number of places per country was:
- USA, 15 places
- England, 10 places
- Canada, 7 places
- New Zealand, 5 places
- Australia, 4 places
- Kenya, 4 places
- Thailand, 4 places
- Ghana, 3 places
- Philippines, 3 places
- Nigeria, 3 places
- Singapore, 3 places
- Sri Lanka, 3 places
- Bahrain, 2 places
- India, 2 places
- Israel, 2 places
- Japan, 2 places
- Malaysia, 2 places
- Malta, 2 places
- Oman, 2 places
- Pakistan, 2 places
- Scotland, 2 places
- South Africa, 2 places
- Wales, 2 places
- Cameroon, 1 place
- France, 1 place
- Gibraltar, 1 place
- Guyana, 1 place
- Indonesia, 1 place
- Ireland, 1 place
- Kurdistan-Iraq, 1 place
- Kuwait, 1 place
- Poland, 1 place
- Romania, 1 place
- Saudi Arabia, 1 place
- Seychelles, 1 place
- Sweden, 1 place
- Tanzania, 1 place
- Trinidad, 1 place
- U.A.E., 1 place
- Uganda, 1 place
- Zambia, 1 place
Panupol Sujjayakorn qualified automatically as defending World Champion, and so did not count towards Thailand's quota.
