Wilson, Lincoln County, Wisconsin

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Wilson is a town in Lincoln County, Wisconsin, United States. The population was 299 at the 2000 census.

[edit] Geography

According to the United States Census Bureau, the town has a total area of 94.1 km² (36.3 mi²). 91.1 km² (35.2 mi²) of it is land and 3.0 km² (1.2 mi²) of it (3.22%) is water.

[edit] Demographics

As of the census ² of 2000, there were 299 people, 130 households, and 92 families residing in the town. The population density was 3.3/km² (8.5/mi²). There were 334 housing units at an average density of 3.7/km² (9.5/mi²). The racial makeup of the town was 98.66% White, 0.33% Asian, and 1.00% from two or more races.

There were 130 households out of which 21.5% had children under the age of 18 living with them, 64.6% were married couples living together, 3.1% had a female householder with no husband present, and 29.2% were non-families. 22.3% of all households were made up of individuals and 13.1% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 2.64.

In the town the population was spread out with 18.1% under the age of 18, 5.0% from 18 to 24, 22.7% from 25 to 44, 32.8% from 45 to 64, and 21.4% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 95.4 males. For every 100 females age 18 and over, there were 100.8 males.

The median income for a household in the town was $32,750, and the median income for a family was $38,125. Males had a median income of $32,321 versus $20,625 for females. The per capita income for the town was $16,103. About 11.0% of families and 13.1% of the population were below the poverty line, including 18.9% of those under the age of eighteen and 12.5% of those sixty five or over.