Wiener-Hopf

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The Wiener-Hopf technique was developed to solve Fourier transform problems with mixed conditions on the same boundary, by exploiting the complex-analytical properties of the transformed function.

[edit] Example

Let us consider the linear partial differential equation

\boldsymbol{L}_{xy}f(x,y)=0,

where \boldsymbol{L}_{xy} is a linear operator which contains derivatives with respect to x and y, subject to the mixed conditions on y = 0, for some prescribed function g(x),

f = g(x) for x\geq 0,


fy = 0 when x < 0.

and decay at infinity i.e. f\rightarrow 0 as \boldsymbol{x}\rightarrow \infty. Taking a Fourier transform with respect to x results in the following ODE

\boldsymbol{L}_{y}\hat{f}(k,y)-P(k,y)\hat{f}(k,y)=0,

where \boldsymbol{L}_{y} is a linear operator containing y derivatives only, P(k,y) is a known function of y and k and

\hat{f}(k)=\int_{-\infty}^{\infty} f(x,y)e^{-ikx}\textrm{d}x.

If a particular solution of the ODE which satisfies the necessary decay at infinity is denoted \hat{F}(k,y), a general solution can be written as

\hat{f}=C(k)\hat{F}(k,y)

where C(k) is an unknown function to be determined by the boundary conditions on y = 0.

The key idea is to split \hat{f} into two separate functions, \hat{f}_{+} and \hat{f}_{-} which are analytic in the lower- and upper-halves of the complex plane, respectively

\hat{f}_{+}(k,y)=\int_{0}^{\infty} f(x,y)e^{-ikx}\textrm{d}x,
\hat{f}_{-}(k,y)=\int_{-\infty}^{0} f(x,y)e^{-ikx}\textrm{d}x.

The boundary conditions then give

\hat{f}_{-}(k,0)+\hat{f}_{+}(k,0) = \hat{g}(k)+\hat{f}_{+}(k,0) = C(k)F(k,0)


and, on taking derivatives with respect to y,

\hat{f}'_{-}(k,0)+\hat{f}'_{+}(k,0) = \hat{f}'_{-}(k,0) = C(k)F'(k,0).

Eliminating C(k) yields

\hat{g}(k)+\hat{f}_{+}(k,0) - \hat{f}'_{-}(k,0)/K(k) = 0,

where

K(k) = \frac{F'(k,0)}{F(k,0)}.

Now K(k) can be decomposed into the product of functions K and K + which analytic in the upper-half plane or lower-half plane, respectively

K(k) = K + (k)K (k),


\hbox{log} K^{-} = \frac{1}{2\pi i}\int_{-\infty}^{\infty} \frac{\hbox{log}(K(z))}{z-k} \textrm{d}z, \quad \hbox{Im}k>0,
\hbox{log} K^{+} = -\frac{1}{2\pi i}\int_{-\infty}^{\infty} \frac{\hbox{log}(K(z))}{z-k} \textrm{d}z, \quad \hbox{Im}k<0.

Consequently

K_{+}(k)\hat{g}_{+}(k) + K_{+}(k)\hat{f}_{+}(k,0) = \hat{f}'_{-}(k,0)/K_{-}(k) - K_{+}(k)\hat{g}_{-}(k),

where it has been assumed that g can be broken down into functions analytic in the lower-half plane g + and upper-half plane g , respectively. Now, as the left-hand side of the above equation is analytic in the lower-half plane, whilst the right-hand side is analytic in the upper-half plane, analytic continution guarantees existence of an entire function which coincides with the left- or right-hand sides in their respective half-planes. Furthermore, since it can be shown that the functions on either side of the above equation decay at large k, Liouville's theorem (complex analysis) tells us that this entire function is identically zero, therefore

\hat{f}_{+}(k,0) = -\hat{g}_{+}(k),

and so

C(k) = \frac{\hat{g}(k)-\hat{g}_{+}(k)}{F(k,0)}.

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