Wheatland, Indiana

From Wikipedia, the free encyclopedia

Wheatland is a town in Knox County, Indiana, United States. The population was 504 at the 2000 census.

[edit] Geography

Wheatland is located at 38°39′51″N, 87°18′28″W (38.664166, -87.307775)^GR1.

According to the United States Census Bureau, the town has a total area of 1.1 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 504 people, 206 households, and 138 families residing in the town. The population density was 474.6/km² (1,218.2/mi²). There were 235 housing units at an average density of 221.3/km² (568.0/mi²). The racial makeup of the town was 98.61% White, 0.40% African American, 0.20% Native American, 0.40% from other races, and 0.40% from two or more races. Hispanic or Latino of any race were 0.60% of the population.

There were 206 households out of which 33.5% had children under the age of 18 living with them, 51.5% were married couples living together, 11.7% had a female householder with no husband present, and 33.0% were non-families. 29.1% of all households were made up of individuals and 11.7% had someone living alone who was 65 years of age or older. The average household size was 2.43 and the average family size was 3.01.

In the town the population was spread out with 27.2% under the age of 18, 8.5% from 18 to 24, 30.2% from 25 to 44, 21.6% from 45 to 64, and 12.5% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 90.9 males. For every 100 females age 18 and over, there were 94.2 males.

The median income for a household in the town was $27,174, and the median income for a family was $36,818. Males had a median income of $28,750 versus $21,458 for females. The per capita income for the town was $14,646. About 12.1% of families and 16.3% of the population were below the poverty line, including 18.9% of those under age 18 and 8.1% of those age 65 or over.