Wellsburg, Iowa

From Wikipedia, the free encyclopedia

Wellsburg is a city in Grundy County, Iowa, USA. The population was 716 at the 2000 census.

[edit] Geography

Wellsburg is located at 42°26′1″N, 92°55′41″W (42.433723, -92.928172)^GR1.

According to the United States Census Bureau, the city has a total area of 2.6 km² (1.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 716 people, 338 households, and 201 families residing in the city. The population density was 279.2/km² (725.6/mi²). There were 363 housing units at an average density of 141.6/km² (367.8/mi²). The racial makeup of the city was 98.88% White, 0.42% Asian, and 0.70% from two or more races.

There were 338 households out of which 23.4% had children under the age of 18 living with them, 53.0% were married couples living together, 4.7% had a female householder with no husband present, and 40.5% were non-families. 37.9% of all households were made up of individuals and 26.6% had someone living alone who was 65 years of age or older. The average household size was 2.12 and the average family size was 2.81.

In the city the population was spread out with 21.8% under the age of 18, 4.6% from 18 to 24, 22.3% from 25 to 44, 23.0% from 45 to 64, and 28.2% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 82.7 males. For every 100 females age 18 and over, there were 78.9 males.

The median income for a household in the city was $30,417, and the median income for a family was $38,750. Males had a median income of $30,724 versus $21,250 for females. The per capita income for the city was $17,636. About 4.5% of families and 6.0% of the population were below the poverty line, including 3.9% of those under age 18 and 8.6% of those age 65 or over.