Talk:Wavelet compression

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"This produces as many coefficients as there are pixels...". This statement doesn't seem to be correct. A wavelet transform can produce any amount of coefficients, depending on how many wavelets are considered in that process.

[edit] Lossy?

A certain loss of quality is accepted, known as lossy compression.

I'm not sure why this line is placed right in the beginning of the article - wavelet transforms are not inherently lossy - that comes purely from their finite precision implementation. Furthermore, you do have integer wavelet transforms that are prefectly lossless.

--Brokentooth 23:06, 20 July 2006 (UTC)

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