Wauneta, Nebraska

From Wikipedia, the free encyclopedia

Wauneta is a village in Chase County, Nebraska, United States. The population was 625 at the 2000 census.

[edit] Geography

Wauneta is located at 40°25'1" North, 101°22'19" West (40.417072, -101.372019)^GR1.

According to the United States Census Bureau, the village has a total area of 2.0 km² (0.8 mi²) of land and none of it is covered by water.

[edit] Demographics

As of the census^GR2 of 2000, there were 625 people, 280 households, and 180 families residing in the village. The population density was 317.5/km² (817.4/mi²). There were 325 housing units at an average density of 165.1/km² (425.1/mi²). The racial makeup of the village was 96.16% White, 0.16% Black or African American, none Native American, 0.48% Asian, 0.16% Pacific Islander, 2.72% from other races, and 0.32% from two or more races. Hispanic or Latino of any race were 2.72% of the population.

There were 280 households out of which 23.2% had children under the age of 18 living with them, 56.1% were married couples living together, 5.7% had a female householder with no husband present, and 35.7% were non-families. 32.9% of all households were made up of individuals and 17.5% had someone living alone who was 65 years of age or older. The average household size was 2.11 and the average family size was 2.65.

In the village the population was spread out with 18.6% under the age of 18, 5.1% from 18 to 24, 20.6% from 25 to 44, 21.6% from 45 to 64, and 34.1% who were 65 years of age or older. The median age was 50 years. For every 100 females there were 89.4 males. For every 100 females age 18 and over, there were 89.9 males.

The median income for a household in the village was $29,813, and the median income for a family was $33,500. Males had a median income of $24,750 versus $16,932 for females. The per capita income for the village was $16,385. About 7.2% of families and 9.1% of the population were below the poverty line, including 16.8% of those under age 18 and 6.1% of those age 65 or over.