Watson, Arkansas

From Wikipedia, the free encyclopedia

Watson is a city in Desha County, Arkansas, United States. The population was 288 at the 2000 census.

[edit] Geography

Watson is located at 33°53′33″N, 91°15′24″W (33.892511, -91.256688)^GR1.

According to the United States Census Bureau, the city has a total area of 0.5 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 288 people, 113 households, and 78 families residing in the city. The population density was 556.0/km² (1,414.6/mi²). There were 125 housing units at an average density of 241.3/km² (614.0/mi²). The racial makeup of the city was 72.57% White, 24.65% Black or African American, 0.69% Native American, 0.69% Pacific Islander, and 1.39% from two or more races.

There were 113 households out of which 25.7% had children under the age of 18 living with them, 48.7% were married couples living together, 12.4% had a female householder with no husband present, and 30.1% were non-families. 28.3% of all households were made up of individuals and 17.7% had someone living alone who was 65 years of age or older. The average household size was 2.55 and the average family size was 3.10.

In the city the population was spread out with 24.0% under the age of 18, 7.3% from 18 to 24, 19.8% from 25 to 44, 26.0% from 45 to 64, and 22.9% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 94.6 males. For every 100 females age 18 and over, there were 87.2 males.

The median income for a household in the city was $17,143, and the median income for a family was $33,889. Males had a median income of $30,625 versus $15,313 for females. The per capita income for the city was $13,631. About 22.6% of families and 25.8% of the population were below the poverty line, including 40.5% of those under the age of eighteen and 23.0% of those sixty five or over.