Waterbury, Nebraska

From Wikipedia, the free encyclopedia

Waterbury is a village in Dixon County, Nebraska, United States. It is part of the Sioux City/Iowa/Nebraska/South Dakota Metropolitan Statistical Area. The population was 89 at the 2000 census.

[edit] Geography

Waterbury is located at 42°27′26″N, 96°44′8″W (42.457204, -96.735558)^GR1.

According to the United States Census Bureau, the village has a total area of 0.4 km² (0.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 89 people, 34 households, and 21 families residing in the village. The population density was 245.5/km² (645.9/mi²). There were 46 housing units at an average density of 126.9/km² (333.8/mi²). The racial makeup of the village was 100.00% White.

There were 34 households out of which 35.3% had children under the age of 18 living with them, 41.2% were married couples living together, 14.7% had a female householder with no husband present, and 35.3% were non-families. 29.4% of all households were made up of individuals and 11.8% had someone living alone who was 65 years of age or older. The average household size was 2.62 and the average family size was 3.36.

In the village the population was spread out with 32.6% under the age of 18, 2.2% from 18 to 24, 37.1% from 25 to 44, 18.0% from 45 to 64, and 10.1% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 122.5 males. For every 100 females age 18 and over, there were 106.9 males.

The median income for a household in the village was $23,438, and the median income for a family was $41,458. Males had a median income of $25,938 versus $23,906 for females. The per capita income for the village was $14,764. There were 13.3% of families and 19.8% of the population living below the poverty line, including 22.2% of under eighteens and 28.6% of those over 64.