Wallula, Washington

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Wallula is a census-designated place (CDP) in Walla Walla County, Washington, United States. The population was 197 at the 2000 census.

[edit] Geography

Wallula is located at 46°5′4″N, 118°54′23″W (46.084446, -118.906256)^GR1.

According to the United States Census Bureau, the CDP has a total area of 0.3 km² (0.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 197 people, 60 households, and 48 families residing in the CDP. The population density was 760.6/km² (1,978.5/mi²). There were 64 housing units at an average density of 247.1/km² (642.8/mi²). The racial makeup of the CDP was 87.31% White, 1.02% Native American, 11.68% from other races. Hispanic or Latino of any race were 16.75% of the population.

There were 60 households out of which 45.0% had children under the age of 18 living with them, 61.7% were married couples living together, 11.7% had a female householder with no husband present, and 20.0% were non-families. 8.3% of all households were made up of individuals and 1.7% had someone living alone who was 65 years of age or older. The average household size was 3.28 and the average family size was 3.38.

In the CDP the population was spread out with 39.6% under the age of 18, 2.5% from 18 to 24, 26.9% from 25 to 44, 20.8% from 45 to 64, and 10.2% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 91.3 males. For every 100 females age 18 and over, there were 83.1 males.

The median income for a household in the CDP was $26,071, and the median income for a family was $26,071. Males had a median income of $26,000 versus $18,611 for females. The per capita income for the CDP was $10,831. About 7.4% of families and 11.7% of the population were below the poverty line, including 18.7% of those under the age of eighteen and none of those sixty five or over.