Unionville, Iowa

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Unionville is a city in Appanoose County, Iowa, United States. The population was 127 at the 2000 census.

[edit] Geography

Location of Unionville, Iowa

Unionville is located at 40°49′7″N, 92°41′40″W (40.818515, -92.694443)GR1.

According to the United States Census Bureau, the city has a total area of 1.9 km² (0.7 mi²), all land.

[edit] Demographics

As of the censusGR2 of 2000, there were 127 people, 50 households, and 38 families residing in the city. The population density was 66.3/km² (170.5/mi²). There were 68 housing units at an average density of 35.5/km² (91.3/mi²). The racial makeup of the city was 100.00% White.

There were 50 households out of which 38.0% had children under the age of 18 living with them, 64.0% were married couples living together, 8.0% had a female householder with no husband present, and 24.0% were non-families. 24.0% of all households were made up of individuals and 12.0% had someone living alone who was 65 years of age or older. The average household size was 2.54 and the average family size was 3.00.

In the city the population was spread out with 26.8% under the age of 18, 5.5% from 18 to 24, 24.4% from 25 to 44, 18.9% from 45 to 64, and 24.4% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 89.6 males. For every 100 females age 18 and over, there were 86.0 males.

The median income for a household in the city was $33,333, and the median income for a family was $44,375. Males had a median income of $26,250 versus $19,375 for females. The per capita income for the city was $13,856. There were 9.1% of families and 11.3% of the population living below the poverty line, including 22.2% of under eighteens and none of those over 64.

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