Tingley, Iowa

From Wikipedia, the free encyclopedia

Tingley is a city in Ringgold County, Iowa, United States. The population was 171 at the 2000 census.

[edit] Geography

Tingley is located at 40°51′10″N, 94°11′45″W (40.852753, -94.195767)^GR1.

According to the United States Census Bureau, the city has a total area of 1.7 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 171 people, 87 households, and 44 families residing in the city. The population density was 98.5/km² (253.6/mi²). There were 109 housing units at an average density of 62.8/km² (161.6/mi²). The racial makeup of the city was 98.25% White, and 1.75% from two or more races. Hispanic or Latino of any race were 0.58% of the population.

There were 87 households out of which 19.5% had children under the age of 18 living with them, 42.5% were married couples living together, 6.9% had a female householder with no husband present, and 48.3% were non-families. 46.0% of all households were made up of individuals and 33.3% had someone living alone who was 65 years of age or older. The average household size was 1.97 and the average family size was 2.78.

In the city the population was spread out with 19.9% under the age of 18, 6.4% from 18 to 24, 20.5% from 25 to 44, 27.5% from 45 to 64, and 25.7% who were 65 years of age or older. The median age was 49 years. For every 100 females there were 81.9 males. For every 100 females age 18 and over, there were 69.1 males.

The median income for a household in the city was $22,321, and the median income for a family was $34,375. Males had a median income of $26,250 versus $22,222 for females. The per capita income for the city was $14,475. About 7.7% of families and 10.1% of the population were below the poverty line, including 2.7% of those under the age of eighteen and 19.0% of those sixty five or over.