Thayer, Iowa

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Thayer is a city in Union County, Iowa, United States. As of the 2000 census, the city population was 66.

1 Geography
2 Demographics
3 See also
4 External links

[edit] Geography

Thayer is located at 41°1'45" North, 94°2'59" West (41.029242, -94.049856)^GR1.

According to the United States Census Bureau, the city has a total area of 0.3 km² (0.1 mi²), all of it land.

[edit] Demographics

As of the census^GR2 of 2000, there were 66 people, 26 households, and 15 families residing in the city. The population density was 254.8/km² (672.7/mi²). There were 35 housing units at an average density of 135.1/km² (356.7/mi²). The racial makeup of the city was 96.97% White and 3.03% Native American.

There were 26 households out of which 26.9% had children under the age of 18 living with them, 46.2% were married couples living together, none have a female householder with no husband present, and 38.5% were non-families. 26.9% of all households were made up of individuals and 15.4% had someone living alone who was 65 years of age or older. The average household size was 2.54 and the average family size was 3.06.

In the city the population was spread out with 25.8% under the age of 18, 12.1% from 18 to 24, 33.3% from 25 to 44, 18.2% from 45 to 64, and 10.6% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 112.9 males. For every 100 females age 18 and over, there were 104.2 males.

The median income for a household in the city was $31,250, and the median income for a family was $38,750. Males had a median income of $21,667 versus $12,500 for females. The per capita income for the city was $13,705. 6.3% of the population but no families are below the poverty line. Out of the total population, none of those under the age of 18 and 25.0% of those 65 and older were living below the poverty line.