Table Rock, Wyoming

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Table Rock is a census-designated place in Sweetwater County, Wyoming, United States. The population was 82 at the 2000 census.

[edit] Geography

Table Rock is located at 41°37′34″N, 108°23′17″W (41.626004, -108.387971)^GR1.

According to the United States Census Bureau, the CDP has a total area of 17.6 km² (6.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 82 people, 32 households, and 23 families residing in the CDP. The population density was 4.6/km² (12.0/mi²). There were 55 housing units at an average density of 3.1/km² (8.1/mi²). The racial makeup of the CDP was 86.59% White, 1.22% Native American, 1.22% Asian, 3.66% from other races, and 7.32% from two or more races. Hispanic or Latino of any race were 10.98% of the population.

There were 32 households out of which 43.8% had children under the age of 18 living with them, 65.6% were married couples living together, 3.1% had a female householder with no husband present, and 28.1% were non-families. 28.1% of all households were made up of individuals and none had someone living alone who was 65 years of age or older. The average household size was 2.56 and the average family size was 3.17.

In the CDP the population was spread out with 32.9% under the age of 18, 12.2% from 18 to 24, 30.5% from 25 to 44, 24.4% from 45 to 64, . The median age was 29 years. For every 100 females there were 121.6 males. For every 100 females age 18 and over, there were 150.0 males.

The median income for a household in the CDP was $48,750, and the median income for a family was $48,750. Males had a median income of $41,000 versus $11,250 for females. The per capita income for the CDP was $12,775. None of the population or the families were below the poverty line.