Sylvan Springs, Alabama

From Wikipedia, the free encyclopedia

Sylvan Springs is a town in Jefferson County, Alabama, United States. At the 2000 census the population was 1,465.

[edit] Geography

Sylvan Springs is located at 33°30′46″N, 87°1′14″W (33.512650, -87.020636)^GR1.

According to the U.S. Census Bureau, the town has a total area of 9.0 km² (3.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,465 people, 589 households, and 461 families residing in the town. The population density was 162.1/km² (420.3/mi²). There were 610 housing units at an average density of 67.5/km² (175.0/mi²). The racial makeup of the town was 98.63% White, 0.68% Black or African American, 0.34% Native American, 0.07% Asian, and 0.27% from two or more races. 0.48% of the population were Hispanic or Latino of any race.

There were 589 households out of which 26.1% had children under the age of 18 living with them, 68.6% were married couples living together, 7.3% had a female householder with no husband present, and 21.7% were non-families. 19.9% of all households were made up of individuals and 10.7% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 2.85.

In the town the population was spread out with 18.0% under the age of 18, 8.7% from 18 to 24, 26.6% from 25 to 44, 28.6% from 45 to 64, and 18.2% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 93.5 males. For every 100 females age 18 and over, there were 89.1 males.

The median income for a household in the town was $42,692, and the median income for a family was $49,853. Males had a median income of $37,500 versus $23,350 for females. The per capita income for the town was $20,338. About 3.9% of families and 4.7% of the population were below the poverty line, including 5.0% of those under age 18 and 7.8% of those age 65 or over.