Stockholm, Wisconsin

From Wikipedia, the free encyclopedia

Stockholm is a village in Pepin County, Wisconsin, USA, founded in 1854 by immigrants from Karlskoga, Sweden. The population was 97 at the 2000 census. The village is located within the Town of Stockholm.

1 Geography
2 Demographics
3 See also
4 External links

[edit] Geography

Stockholm is located at 44°28′52″N, 92°15′34″W (44.481326, -92.259653)^GR1.

According to the United States Census Bureau, the village has a total area of 2.5 km² (1.0 mi²). 2.4 km² (0.9 mi²) of it is land and 0.1 km² (0.04 mi²) of it (3.12%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 97 people, 48 households, and 30 families residing in the village. The population density was 40.3/km² (104.0/mi²). There were 89 housing units at an average density of 36.9/km² (95.4/mi²). The racial makeup of the village was 100.00% white and none of other races.

There were 48 households out of which 16.7% had children under the age of 18 living with them, 56.3% were married couples living together, 4.2% had a female householder with no husband present, and 37.5% were non-families. 31.3% of all households were made up of individuals and 6.3% had someone living alone who was 65 years of age or older. The average household size was 2.02 and the average family size was 2.53.

In the village the population was spread out with 15.5% under the age of 18, 6.2% from 18 to 24, 14.4% from 25 to 44, 42.3% from 45 to 64, and 21.6% who were 65 years of age or older. The median age was 52 years. For every 100 females there were 120.5 males. For every 100 females age 18 and over, there were 121.6 males.

The median income for a household in the village was $41,250, and the median income for a family was $46,250. Males had a median income of $26,250 versus $26,667 for females. The per capita income for the village was $55,006. 8.6% of the population is below the poverty line. Out of the total population, no one is below the age of 18 or over the age of 65.