Stockdale, Texas

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Stockdale is a city in Wilson County, Texas, United States. The population was 1,398 at the 2000 census.

1 Geography
2 Demographics
3 Education
4 External links

[edit] Geography

Stockdale is located at 29°14′0″N, 97°57′43″W (29.233371, -97.961987)^GR1.

According to the United States Census Bureau, the city has a total area of 4.2 km² (1.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,398 people, 497 households, and 337 families residing in the city. The population density was 333.2/km² (865.3/mi²). There were 556 housing units at an average density of 132.5/km² (344.2/mi²). The racial makeup of the city was 74.54% White, 2.36% African American, 0.21% Native American, 0.14% Asian, 21.03% from other races, and 1.72% from two or more races. Hispanic or Latino of any race were 45.99% of the population.

There were 497 households out of which 34.0% had children under the age of 18 living with them, 53.3% were married couples living together, 10.3% had a female householder with no husband present, and 32.0% were non-families. 28.4% of all households were made up of individuals and 16.1% had someone living alone who was 65 years of age or older. The average household size was 2.68 and the average family size was 3.33.

In the city the population was spread out with 26.5% under the age of 18, 8.5% from 18 to 24, 25.6% from 25 to 44, 20.2% from 45 to 64, and 19.2% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 93.4 males. For every 100 females age 18 and over, there were 86.9 males.

The median income for a household in the city was $30,337, and the median income for a family was $39,667. Males had a median income of $29,583 versus $20,395 for females. The per capita income for the city was $15,102. About 10.8% of families and 14.5% of the population were below the poverty line, including 15.5% of those under age 18 and 20.9% of those age 65 or over.