Spiritwood Lake, North Dakota

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Spiritwood Lake is a city in Stutsman County, North Dakota in the United States. The population was 72 at the 2000 census.

[edit] Geography

Spiritwood Lake is located at 47°4′35″N, 98°34′29″W (47.076276, -98.574683)^GR1.

According to the United States Census Bureau, the city has a total area of 4.7 km² (1.8 mi²). 2.8 km² (1.1 mi²) of it is land and 1.9 km² (0.7 mi²) of it (40.00%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 72 people, 31 households, and 23 families residing in the city. The population density was 25.7/km² (66.5/mi²). There were 63 housing units at an average density of 22.5/km² (58.2/mi²). The racial makeup of the city was 100.00% White.

There were 31 households out of which 25.8% had children under the age of 18 living with them, 74.2% were married couples living together, 3.2% had a female householder with no husband present, and 22.6% were non-families. 19.4% of all households were made up of individuals and 6.5% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.67.

In the city the population was spread out with 19.4% under the age of 18, 1.4% from 18 to 24, 25.0% from 25 to 44, 37.5% from 45 to 64, and 16.7% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 125.0 males. For every 100 females age 18 and over, there were 114.8 males.

The median income for a household in the city was $43,500, and the median income for a family was $45,625. Males had a median income of $22,500 versus $14,375 for females. The per capita income for the city was $24,637. None of the population and none of the families were below the poverty line.