Simpsonville, Kentucky

From Wikipedia, the free encyclopedia

Simpsonville is a city in Shelby County, Kentucky, United States. The population was 1,281 at the 2000 census.

[edit] Geography

Simpsonville is located at 38°13′6″N, 85°21′11″W (38.218373, -85.353058)^GR1.

According to the United States Census Bureau, the city has a total area of 3.4 km² (1.3 mi²). 3.4 km² (1.3 mi²) of it is land and 0.1 km² (0.04 mi²) of it (1.50%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,281 people, 489 households, and 352 families residing in the city. The population density was 377.6/km² (980.9/mi²). There were 517 housing units at an average density of 152.4/km² (395.9/mi²). The racial makeup of the city was 85.87% White, 6.01% African American, 0.47% Native American, 0.55% Asian, 5.62% from other races, and 1.48% from two or more races. Hispanic or Latino of any race were 7.49% of the population.

There were 489 households out of which 44.2% had children under the age of 18 living with them, 54.8% were married couples living together, 13.7% had a female householder with no husband present, and 28.0% were non-families. 23.3% of all households were made up of individuals and 6.1% had someone living alone who was 65 years of age or older. The average household size was 2.62 and the average family size was 3.09.

In the city the population was spread out with 30.7% under the age of 18, 6.7% from 18 to 24, 38.1% from 25 to 44, 16.5% from 45 to 64, and 8.0% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 91.5 males. For every 100 females age 18 and over, there were 88.5 males.

The median income for a household in the city was $45,000, and the median income for a family was $52,560. Males had a median income of $34,688 versus $27,431 for females. The per capita income for the city was $17,443. About 7.7% of families and 6.5% of the population were below the poverty line, including 6.3% of those under age 18 and 7.2% of those age 65 or over.