Sherry, Wisconsin

From Wikipedia, the free encyclopedia

Sherry is a town in Wood County, Wisconsin, United States. The population was 809 at the 2000 census.

[edit] Geography

According to the United States Census Bureau, the town has a total area of 91.6 km² (35.4 mi²). 91.3 km² (35.3 mi²) of it is land and 0.3 km² (0.1 mi²) of it (0.34%) is water.

[edit] Demographics

As of the census ² of 2000, there were 809 people, 270 households, and 217 families residing in the town. The population density was 8.9/km² (22.9/mi²). There were 280 housing units at an average density of 3.1/km² (7.9/mi²). The racial makeup of the town was 96.79% White, 0.25% Native American, 1.36% Asian, 0.49% from other races, and 1.11% from two or more races. Hispanic or Latino of any race were 0.99% of the population.

There were 270 households out of which 44.4% had children under the age of 18 living with them, 70.7% were married couples living together, 5.9% had a female householder with no husband present, and 19.3% were non-families. 14.8% of all households were made up of individuals and 4.1% had someone living alone who was 65 years of age or older. The average household size was 3.00 and the average family size was 3.36.

In the town the population was spread out with 30.8% under the age of 18, 8.7% from 18 to 24, 30.7% from 25 to 44, 20.6% from 45 to 64, and 9.3% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 103.8 males. For every 100 females age 18 and over, there were 105.9 males.

The median income for a household in the town was $52,143, and the median income for a family was $53,036. Males had a median income of $33,250 versus $25,341 for females. The per capita income for the town was $17,728. About 1.8% of families and 2.3% of the population were below the poverty line, including 1.9% of those under age 18 and 2.6% of those age 65 or over.