Seaforth, Minnesota
From Wikipedia, the free encyclopedia
Seaforth is a city in Redwood County, Minnesota, United States. The population was 77 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the city has a total area of 2.6 km² (1.0 mi²), all land.
[edit] Demographics
As of the census2 of 2000, there were 77 people, 37 households, and 20 families residing in the city. The population density was 29.4/km² (76.3/mi²). There were 41 housing units at an average density of 15.7/km² (40.6/mi²). The racial makeup of the city was 100.00% White.
There were 37 households out of which 18.9% had children under the age of 18 living with them, 45.9% were married couples living together, 8.1% had a female householder with no husband present, and 45.9% were non-families. 40.5% of all households were made up of individuals and 13.5% had someone living alone who was 65 years of age or older. The average household size was 2.08 and the average family size was 2.90.
In the city the population was spread out with 22.1% under the age of 18, 1.3% from 18 to 24, 24.7% from 25 to 44, 28.6% from 45 to 64, and 23.4% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 92.5 males. For every 100 females age 18 and over, there were 87.5 males.
The median income for a household in the city was $27,143, and the median income for a family was $26,875. Males had a median income of $29,375 versus $22,500 for females. The per capita income for the city was $15,089. There were 9.5% of families and 9.4% of the population living below the poverty line, including 66.7% of under eighteens and none of those over 64.
