Sandusky, Michigan
From Wikipedia, the free encyclopedia
Sandusky is a city in the U.S. state of Michigan. As of the 2000 census, the city population was 2,745. It is the county seat of Sanilac County6.
[edit] Geography
According to the United States Census Bureau, the city has a total area of 4.9 km² (1.9 mi²), all land.
[edit] Demographics
As of the census2 of 2000, there were 2,745 people, 1,081 households, and 649 families residing in the city. The population density was 557.8/km² (1,446.3/mi²). There were 1,168 housing units at an average density of 237.4/km² (615.4/mi²). The racial makeup of the city was 95.12% White, 0.87% African American, 0.15% Native American, 1.75% Asian, 1.35% from other races, and 0.77% from two or more races. Hispanic or Latino of any race were 3.42% of the population.
There were 1,081 households out of which 31.2% had children under the age of 18 living with them, 43.6% were married couples living together, 13.0% had a female householder with no husband present, and 39.9% were non-families. 35.9% of all households were made up of individuals and 16.7% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.97.
In the city the population was spread out with 22.8% under the age of 18, 9.3% from 18 to 24, 29.5% from 25 to 44, 19.6% from 45 to 64, and 18.8% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 86.5 males. For every 100 females age 18 and over, there were 85.8 males.
The median income for a household in the city was $33,667, and the median income for a family was $44,622. Males had a median income of $31,531 versus $20,932 for females. The per capita income for the city was $17,639. About 7.2% of families and 11.0% of the population were below the poverty line, including 8.9% of those under age 18 and 14.0% of those age 65 or over.
