Sanborn, Minnesota

From Wikipedia, the free encyclopedia

Sanborn is a city in Redwood County, Minnesota, United States. The population was 434 at the 2000 census.

[edit] Geography

According to the United States Census Bureau, the city has a total area of 5.5 km² (2.1 mi²), all land.

[edit] Demographics

As of the census ² of 2000, there were 434 people, 179 households, and 127 families residing in the city. The population density was 78.7/km² (203.8/mi²). There were 199 housing units at an average density of 36.1/km² (93.4/mi²). The racial makeup of the city was 99.08% White and 0.92% Native American. Hispanic or Latino of any race were 0.69% of the population.

There were 179 households out of which 31.8% had children under the age of 18 living with them, 60.9% were married couples living together, 6.1% had a female householder with no husband present, and 28.5% were non-families. 27.4% of all households were made up of individuals and 16.8% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 2.93.

In the city the population was spread out with 26.3% under the age of 18, 8.3% from 18 to 24, 21.2% from 25 to 44, 22.6% from 45 to 64, and 21.7% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 102.5 males.

The median income for a household in the city was $36,375, and the median income for a family was $47,813. Males had a median income of $25,682 versus $21,016 for females. The per capita income for the city was $19,809. About 3.0% of families and 6.5% of the population were below the poverty line, including 4.2% of those under age 18 and 3.8% of those age 65 or over.