Rush Valley, Utah

From Wikipedia, the free encyclopedia

Rush Valley is a town in Tooele County, Utah, United States. The population was 453 at the 2000 census.

[edit] Geography

Rush Valley is located at 40°21′33″N, 112°27′17″W (40.359077, -112.454657)^GR1.

According to the United States Census Bureau, the town has a total area of 47.5 km² (18.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 453 people, 149 households, and 123 families residing in the town. The population density was 9.5/km² (24.7/mi²). There were 169 housing units at an average density of 3.6/km² (9.2/mi²). The racial makeup of the town was 98.01% White, 0.22% Native American, 0.22% Pacific Islander, 0.66% from other races, and 0.88% from two or more races. Hispanic or Latino of any race were 1.10% of the population.

There were 149 households out of which 34.9% had children under the age of 18 living with them, 71.8% were married couples living together, 7.4% had a female householder with no husband present, and 16.8% were non-families. 12.8% of all households were made up of individuals and 4.7% had someone living alone who was 65 years of age or older. The average household size was 3.04 and the average family size was 3.34.

In the town the population was spread out with 26.9% under the age of 18, 10.8% from 18 to 24, 24.5% from 25 to 44, 24.9% from 45 to 64, and 12.8% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 102.2 males. For every 100 females age 18 and over, there were 106.9 males.

The median income for a household in the town was $46,875, and the median income for a family was $48,036. Males had a median income of $41,136 versus $22,813 for females. The per capita income for the town was $14,661. About 7.1% of families and 10.4% of the population were below the poverty line, including 15.4% of those under age 18 and 8.3% of those age 65 or over.