Rome, Iowa

From Wikipedia, the free encyclopedia

Rome is a city in Henry County, Iowa, United States. The population was 113 at the 2000 census.

[edit] Geography

Rome is located at 40°58′59″N, 91°40′59″W (40.983047, -91.683033)^GR1.

According to the United States Census Bureau, the city has a total area of 0.3 km² (0.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 113 people, 49 households, and 27 families residing in the city. The population density was 335.6/km² (870.5/mi²). There were 55 housing units at an average density of 163.4/km² (423.7/mi²). The racial makeup of the city was 99.12% White, and 0.88% Native American.

There were 49 households out of which 26.5% had children under the age of 18 living with them, 38.8% were married couples living together, 14.3% had a female householder with no husband present, and 42.9% were non-families. 30.6% of all households were made up of individuals and 4.1% had someone living alone who was 65 years of age or older. The average household size was 2.31 and the average family size was 2.82.

In the city the population was spread out with 24.8% under the age of 18, 8.0% from 18 to 24, 34.5% from 25 to 44, 27.4% from 45 to 64, and 5.3% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 76.6 males. For every 100 females age 18 and over, there were 102.4 males.

The median income for a household in the city was $22,083, and the median income for a family was $40,000. Males had a median income of $26,250 versus $15,625 for females. The per capita income for the city was $12,976. There were 10.0% of families and 27.0% of the population living below the poverty line, including 18.2% of under eighteens and 50.0% of those over 64.