Rock River, Wyoming

From Wikipedia, the free encyclopedia

Rock River is a town in Albany County, Wyoming, in the United States. As of the 2000 census, the town population was 235.

[edit] Geography

Rock River is located at 41°44′27″N, 105°58′29″W (41.740770, -105.974602)^GR1.

According to the United States Census Bureau, the town has a total area of 6.1 km² (2.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 235 people, 94 households, and 67 families residing in the town. The population density was 38.6/km² (100.1/mi²). There were 123 housing units at an average density of 20.2/km² (52.4/mi²). The racial makeup of the town was 96.17% White, 3.40% Native American and 0.43% Asian. Hispanic or Latino of any race were 5.53% of the population.

There were 94 households out of which 29.8% had children under the age of 18 living with them, 61.7% were married couples living together, 5.3% had a female householder with no husband present, and 27.7% were non-families. 24.5% of all households were made up of individuals and 12.8% had someone living alone who was 65 years of age or older. The average household size was 2.50 and the average family size was 2.99.

In the town the population was spread out with 26.8% under the age of 18, 5.1% from 18 to 24, 26.4% from 25 to 44, 26.0% from 45 to 64, and 15.7% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 117.6 males. For every 100 females age 18 and over, there were 104.8 males.

The median income for a household in the town was $24,306, and the median income for a family was $31,250. Males had a median income of $25,250 versus $18,125 for females. The per capita income for the town was $11,602. About 14.1% of families and 24.2% of the population were below the poverty line, including 39.5% of those under the age of eighteen and 26.3% of those sixty five or over.