Republican City, Nebraska

From Wikipedia, the free encyclopedia

Republican City is a village in Harlan County, Nebraska, United States. The population was 209 at the 2000 census.

[edit] Geography

Republican City is located at 40°5′52″N, 99°13′17″W (40.097708, -99.221301)^GR1.

According to the United States Census Bureau, the village has a total area of 0.9 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 209 people, 107 households, and 69 families residing in the village. The population density was 244.5/km² (633.8/mi²). There were 218 housing units at an average density of 255.1/km² (661.1/mi²). The racial makeup of the village was 99.52% White, and 0.48% from two or more races. Hispanic or Latino of any race were 0.96% of the population.

There were 107 households out of which 15.0% had children under the age of 18 living with them, 57.9% were married couples living together, 4.7% had a female householder with no husband present, and 35.5% were non-families. 33.6% of all households were made up of individuals and 20.6% had someone living alone who was 65 years of age or older. The average household size was 1.95 and the average family size was 2.43.

In the village the population was spread out with 12.9% under the age of 18, 5.7% from 18 to 24, 11.0% from 25 to 44, 34.0% from 45 to 64, and 36.4% who were 65 years of age or older. The median age was 60 years. For every 100 females there were 101.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the village was $26,250, and the median income for a family was $32,500. Males had a median income of $27,500 versus $17,917 for females. The per capita income for the village was $14,863. About 6.9% of families and 8.5% of the population were below the poverty line, including 10.5% of those under the age of eighteen and 12.2% of those sixty five or over.