Quasi-phase-matching

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Quasi-phase-matching is a technique in nonlinear optics which allows a positive net flow of energy from the pump frequency to the signal and idler frequencies by creating a periodic structure in the nonlinear medium. Momentum is conserved, as is necessary for phase-matching, through an additional momentum contribution corresponding to the wavevector of the periodic structure. Consequently, in principle any two-wave mixing process that satisfies energy conservation can be phase-matched. For example, all the optical frequencies involved can be collinear, can have the same polarization, and travel through the medium in arbitrary directions. This allows one to use the largest nonlinear coefficient of the material in the nonlinear interaction.

Quasi-phase-matching ensures that there is positive energy flow from the pump frequency to signal and idler frequencies even though all the frequencies involved are not phase locked with each other. Energy will always flow from pump to signal as long the phase between the two optical waves is less than 180 degrees. Beyond 180 degrees, energy flows back from the signal to the pump frequencies. The coherence length is the length of the medium in which the phase of pump and the sum of idler and signal frequencies are 180 degrees from each other. At each coherence length the crystal axes are flipped which allows the energy to continue to positively flow from the pump to the signal and idler frequencies.

The most commonly used technique for creating quasi-phase-matched crystals is periodic poling.^[1]

1 Mathematical description
2 Development of signal amplitude
3 Calculation of domain width
4 References

[edit] Mathematical description

In nonlinear optics, the generation of other frequencies is the result of the nonlinear polarization response of the crystal due to fundamental pump frequency. When the crystal axis is flipped the polarization wave is shifted by 180 degrees thus insuring that there is a positive energy flow to the signal and idler beam. In the case of Difference frequency generation polarization equation can be expressed by.

$P_3=4d A_1 A_2 e^{i(k_1+k_2)z}$

Where $d$ is the nonlinear susceptibility coefficient in which the sign of the coefficient is flipped when the crystal axis is flipped. Where $i$ represents the imaginary unit.

$P_3=-4d A_1 A_2 e^{i(k_1+k_2)z}=4d A_1 A_2 e^{i((k_1+k_2)z+\pi)}$

[edit] Development of signal amplitude

The following mathematical description assumes a constant pump amplitude. The signal wavelength can be expressed as a sum over the number of domains that exists in the crystal. In general the rate for which the energy from the pump wavelength to the signal wavelength is.

$\frac{\partial A_2}{\partial z}=A_1 \chi e^{i \Delta k z}$

Where $A 2$ is the generated frequency amplitude and $A 1$ is the pump frequency amplitude and $Δ k$ is the phase mismatch between the two optical waves. The $χ$ refers to the nonlinear susceptibility of the crystal.

In the case of a periodically poled crystal the optic axis is flipped by 180 degrees which changes the sign of $χ$ . For the $n t h$ domain $χ$ can be express by this function.

$χ = χ 0 ( - 1) n$

Where $n$ is the index of the poled domain. The signal amplitude $A 2$ can be express as a sum.

$A_2=A_1 \chi_0 \sum^{N-1}_{n=0} (-1)^n \int^{\Lambda (n+1)}_{\Lambda n} e^{i \Delta k z} \partial z$

Which integrates to.

$A_2=-\frac{i A_1 \chi_0}{\Delta k} \sum^{N-1}_{n=0} (-1)^n (e^{i \Delta k \Lambda (n+1)}-e^{i \Delta k \Lambda n})$

Which reduce to.

$A_2=-i A_1 \chi_0 \frac{e^{i \Delta k \Lambda}-1}{\Delta k} \sum^{N-1}_{n=0} (-1)^n e^{i \Delta k \Lambda n}$

The summation $s$ can be expressed as a series.

$s=\sum^{N-1}_{n=0} (-1)^n e^{i \Delta k \Lambda n}=1-e^{i \Delta k \Lambda}+e^{i 2 \Delta k \Lambda n}-e^{i 3 \Delta k \Lambda}+...+(-1)^N e^{i \Delta k \Lambda (N-2)}-(-1)^N e^{i \Delta k \Lambda (N-1)}$

Multiply above equation both sides by a factor of $e i Δ k Λ$ .

$s e i Δ k Λ = e i Δ k Λ - e i 2Δ k Λ n + e i 3Δ k Λ + ... + ( - 1) N e i Δ k Λ(N - 1) - ( - 1) N e i Δ k Λ N$

Adding both equation leads to this relation.

$s (1 + e i Δ k Λ) = 1 - ( - 1) N e i Δ k Λ N$

Solving for $s$ .

$s=\frac{1-(-1)^N e^{i \Delta k \Lambda N} }{1+e^{i \Delta k \Lambda}}$

Which leads to $A 2$ to equal.

$A_2=-i A_1 \chi_0 \left( \frac{e^{i \Delta k \Lambda}-1}{\Delta k} \right)\left(\frac{1-(-1)^N e^{i \Delta k \Lambda N}}{e^{i \Delta k \Lambda}+1}\right)$

The total intensity can be expressed by following equation.

$I_2=A_2 A_2^*=A_1^2 \chi_0^2 \Lambda^2 \mbox{sinc}^2(\Delta k \Lambda/2) \left(\frac{1-(-1)^N \cos(\Delta k \Lambda N)}{1+\cos(\Delta k \Lambda)} \right)$

For the case of $\Lambda=\frac{\pi}{\Delta k}$ the right part of the above equation is undefined so the limit needs to be taken when $\Delta k \Lambda \rightarrow \pi$ by invoking L'Hôpital's rule.

$\lim_{\Delta k \Lambda\to\pi}\frac{1-(-1)^N \cos(\Delta k \Lambda N)}{1+\cos(\Delta k \Lambda)}=N^2$

Which leads to intensity relation.

$I_2=\frac{4 A_1^2 \chi_0^2 L^2}{\pi^2}$

In order to allow different domain widths ie. $\Lambda=\frac{i \pi}{\Delta k}$ , for $i = 1,3,5,...$ , the above equation becomes.

$I_2=A_2 A_2^*=A_1^2 \chi_0^2 \Lambda^2 \mbox{sinc}^2(i \Delta k \Lambda/2) \left(\frac{1-(-1)^N \cos(i \Delta k \Lambda N)}{1+\cos(i \Delta k \Lambda)} \right)$

With $\Lambda -> \frac{\pi}{\Delta k}$ the intensity trivially becomes.

$I_2=\frac{4 A_1^2 \chi_0^2 L^2}{i^2 \pi^2}$

From this equation it is apparent that as quasi-phase match order increases the efficiency decreases by that amount. For example for 3rd order quasi-phase matching only a third of the crystal is effectively used for the generation of signal frequency, as a consequence the amplitude of the signal wavelength only third of the amount of amplitude for same length crystal for 1st order quasi-phase match. This allows quasi-phase-matching to exist at different domain widths $Λ$ .

[edit] Calculation of domain width

The domain width is calculated through the use of Sellmeier equation and using wavevector relations. In the case of DFG this relationship holds true $Δ k = k 3 - k 1 - k 2$ where $k 1, k 2,and k 3$ are the pump, signal, and idler wavevectors and $k_i=\frac{2 \pi n(\lambda_i)}{\lambda_i}$ . By calculating $Δ k$ for the different frequencies the domain width can be calculated from the relationship $\Lambda=\frac{\pi}{\Delta k}$ .