Quapaw, Oklahoma

From Wikipedia, the free encyclopedia

Quapaw is a town in Ottawa County, Oklahoma, United States. The population was 984 at the 2000 census.

[edit] Geography

Quapaw is located at 36°57′13″N, 94°47′23″W (36.953673, -94.789602)^GR1.

According to the United States Census Bureau, the town has a total area of 1.5 km² (0.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 984 people, 352 households, and 258 families residing in the town. The population density was 678.4/km² (1,759.4/mi²). There were 423 housing units at an average density of 291.6/km² (756.3/mi²). The racial makeup of the town was 68.60% White, 22.46% Native American, 0.20% Asian, 0.10% from other races, and 8.64% from two or more races. Hispanic or Latino of any race were 1.52% of the population.

There were 352 households out of which 31.5% had children under the age of 18 living with them, 52.8% were married couples living together, 14.2% had a female householder with no husband present, and 26.7% were non-families. 22.4% of all households were made up of individuals and 11.6% had someone living alone who was 65 years of age or older. The average household size was 2.72 and the average family size was 3.16.

In the town the population was spread out with 28.7% under the age of 18, 9.7% from 18 to 24, 22.8% from 25 to 44, 22.9% from 45 to 64, and 16.1% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 97.2 males. For every 100 females age 18 and over, there were 87.2 males.

The median income for a household in the town was $24,083, and the median income for a family was $29,375. Males had a median income of $25,625 versus $17,279 for females. The per capita income for the town was $10,182. About 22.3% of families and 28.3% of the population were below the poverty line, including 41.1% of those under age 18 and 18.1% of those age 65 or over.