Pleasanton, Iowa

From Wikipedia, the free encyclopedia

Pleasanton is a city in Decatur County, Iowa, United States. The population was 37 at the 2000 census.

[edit] Geography

Pleasanton is located at 40°34′49″N, 93°44′35″W (40.580274, -93.743142)^GR1.

According to the United States Census Bureau, the city has a total area of 0.9 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 37 people, 20 households, and 12 families residing in the city. The population density was 42.0/km² (107.6/mi²). There were 24 housing units at an average density of 27.3/km² (69.8/mi²). The racial makeup of the city was 100.00% White.

There were 20 households out of which 15.0% had children under the age of 18 living with them, 55.0% were married couples living together, 5.0% had a female householder with no husband present, and 40.0% were non-families. 40.0% of all households were made up of individuals and 25.0% had someone living alone who was 65 years of age or older. The average household size was 1.85 and the average family size was 2.42.

In the city the population was spread out with 10.8% under the age of 18, 8.1% from 18 to 24, 13.5% from 25 to 44, 35.1% from 45 to 64, and 32.4% who were 65 years of age or older. The median age was 58 years. For every 100 females there were 105.6 males. For every 100 females age 18 and over, there were 94.1 males.

The median income for a household in the city was $51,250, and the median income for a family was $54,375. Males had a median income of $51,250 versus $18,750 for females. The per capita income for the city was $29,231. There were no families and 12.5% of the population living below the poverty line, including no under eighteens and 16.7% of those over 64.