Pine Haven, Wyoming

From Wikipedia, the free encyclopedia

Pine Haven is a town in Crook County, Wyoming, United States. The population was 222 at the 2000 census.

[edit] Geography

Pine Haven is located at 44°21′21″N, 104°48′29″W (44.355948, -104.807991)^GR1.

According to the United States Census Bureau, the town has a total area of 3.4 km² (1.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 222 people, 102 households, and 68 families residing in the town. The population density was 65.4/km² (169.9/mi²). There were 157 housing units at an average density of 46.3/km² (120.2/mi²). The racial makeup of the town was 96.40% White, 1.80% Native American, and 1.80% from two or more races.

There were 102 households out of which 21.6% had children under the age of 18 living with them, 64.7% were married couples living together, 1.0% had a female householder with no husband present, and 33.3% were non-families. 28.4% of all households were made up of individuals and 13.7% had someone living alone who was 65 years of age or older. The average household size was 2.18 and the average family size was 2.68.

In the town the population was spread out with 17.6% under the age of 18, 2.7% from 18 to 24, 21.6% from 25 to 44, 43.7% from 45 to 64, and 14.4% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 107.5 males. For every 100 females age 18 and over, there were 115.3 males.

The median income for a household in the town was $37,250, and the median income for a family was $46,250. Males had a median income of $39,583 versus $35,625 for females. The per capita income for the town was $21,014. About 4.6% of families and 4.1% of the population were below the poverty line, including none of those under the age of eighteen or sixty five or over.