Pike Bay Township, Minnesota
From Wikipedia, the free encyclopedia
Pike Bay Township is a township in Cass County, Minnesota, United States. The population was 1,643 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the township has a total area of 90.0 km² (34.8 mi²). 57.8 km² (22.3 mi²) of it is land and 32.2 km² (12.4 mi²) of it (35.77%) is water.
[edit] Demographics
As of the census2 of 2000, there were 1,643 people, 528 households, and 400 families residing in the township. The population density was 28.4/km² (73.6/mi²). There were 724 housing units at an average density of 12.5/km² (32.4/mi²). The racial makeup of the township was 28.18% White, 68.84% Native American, 0.18% Asian, 0.43% from other races, and 2.37% from two or more races. Hispanic or Latino of any race were 2.62% of the population.
There were 528 households out of which 41.9% had children under the age of 18 living with them, 37.3% were married couples living together, 27.8% had a female householder with no husband present, and 24.1% were non-families. 19.3% of all households were made up of individuals and 6.4% had someone living alone who was 65 years of age or older. The average household size was 3.11 and the average family size was 3.43.
In the township the population was spread out with 36.8% under the age of 18, 10.4% from 18 to 24, 24.7% from 25 to 44, 21.0% from 45 to 64, and 7.1% who were 65 years of age or older. The median age was 28 years. For every 100 females there were 92.4 males. For every 100 females age 18 and over, there were 91.0 males.
The median income for a household in the township was $28,792, and the median income for a family was $27,727. Males had a median income of $26,300 versus $21,400 for females. The per capita income for the township was $10,589. About 22.6% of families and 24.1% of the population were below the poverty line, including 30.1% of those under age 18 and 18.3% of those age 65 or over.
