Template talk:PD-user

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Protected Template:PD-user has been protected indefinitely. Use {{editprotected}} on this page to request an edit.

Contents

[edit] Usage

{{PD-user|username|language code}}
  • Username—The username of the creator.
  • Language code—The two-character ISO 639-2 code (lowercase) that corresponds to the language of the Wikipedia where the user has an account (this is the same as the first two characters in that Wikipedia's domain name—e.g., the German language Wikipedia is found at de.wikipedia.org).

[edit] Discussion

I'd like it better if you could fill in the name with just ~~~ - Omegatron 19:51, May 13, 2005 (UTC)

I saw a page where the link had messed up a bit: Image:Huddersfield1000px.jpg Does that always happen? - Nojer2 07:41, 18 July 2005 (UTC)

{{editprotected}} Suggestion: I think "creator" should be replaced with "copyright holder"--Fallout boy 04:29, 23 December 2005 (UTC)

  • I believe this template is for use only with media actually created by the uploader. howcheng {chat} 20:03, 10 January 2006 (UTC)
That is the crux of my confusion - I have some images that the creator has given permission to use in Wikipedia, for me to put up. This sounds like the tag to use. But of course, how does Wiki know that I actually have valid permission - this tag, as I see it , could be badly misused. --Dumarest 14:49, 23 September 2006 (UTC)
This discussion appears to have been closed. -- Ec5618 16:01, 30 January 2006 (UTC)

[edit] Interwiki link to vi:

Please add an interwiki link to the Vietnamese version of this template:

vi:Tiêu bản:PD-user

Thanks.

 – Minh Nguyễn (talk, contribs) 04:33, 25 January 2006 (UTC)

Added editprotected template. -- Ec5618 16:04, 30 January 2006 (UTC)
Done. howcheng {chat} 19:07, 30 January 2006 (UTC)

[edit] Disclaimers?

Why does this license have "Subject to disclaimers"? Other PD licenses such as {{PD-self}}, {{PD-old}} and {{No rights reserved}} do not have this disclaimer clause. Pengo 01:36, 11 March 2006 (UTC)