Paullina, Iowa

From Wikipedia, the free encyclopedia

Paullina is a city in O'Brien County, Iowa, United States. The population was 1,124 at the 2000 census.

[edit] Geography

Paullina is located at 42°58′43″N, 95°41′13″W (42.978578, -95.687080)^GR1.

According to the United States Census Bureau, the city has a total area of 1.4 km² (0.6 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,124 people, 508 households, and 322 families residing in the city. The population density was 789.1/km² (2,061.6/mi²). There were 547 housing units at an average density of 384.0/km² (1,003.3/mi²). The racial makeup of the city was 99.47% White, 0.18% Native American, 0.09% Asian, and 0.27% from two or more races. Hispanic or Latino of any race were 0.89% of the population.

There were 508 households out of which 21.9% had children under the age of 18 living with them, 55.7% were married couples living together, 5.7% had a female householder with no husband present, and 36.6% were non-families. 34.4% of all households were made up of individuals and 21.5% had someone living alone who was 65 years of age or older. The average household size was 2.14 and the average family size was 2.73.

In the city the population was spread out with 19.9% under the age of 18, 6.4% from 18 to 24, 19.3% from 25 to 44, 23.4% from 45 to 64, and 31.0% who were 65 years of age or older. The median age was 48 years. For every 100 females there were 84.6 males. For every 100 females age 18 and over, there were 80.4 males.

The median income for a household in the city was $32,188, and the median income for a family was $42,569. Males had a median income of $29,293 versus $20,833 for females. The per capita income for the city was $17,644. About 5.1% of families and 9.1% of the population were below the poverty line, including 5.6% of those under age 18 and 12.7% of those age 65 or over.