Oxford Junction, Iowa

From Wikipedia, the free encyclopedia

Oxford Junction is a city in Jones County, Iowa, United States. The population was 573 at the 2000 census.

[edit] Geography

Oxford Junction is located at 41°58′60″N, 90°57′16″W (41.983203, -90.954480)^GR1.

According to the United States Census Bureau, the city has a total area of 1.8 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 573 people, 236 households, and 151 families residing in the city. The population density was 316.1/km² (813.3/mi²). There were 264 housing units at an average density of 145.6/km² (374.7/mi²). The racial makeup of the city was 98.95% White, 0.17% Native American, 0.17% Asian, and 0.70% from two or more races. Hispanic or Latino of any race were 0.17% of the population.

There were 236 households out of which 33.5% had children under the age of 18 living with them, 50.4% were married couples living together, 7.6% had a female householder with no husband present, and 36.0% were non-families. 32.6% of all households were made up of individuals and 22.9% had someone living alone who was 65 years of age or older. The average household size was 2.43 and the average family size was 3.09.

In the city the population was spread out with 27.2% under the age of 18, 8.0% from 18 to 24, 24.1% from 25 to 44, 19.7% from 45 to 64, and 20.9% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 89.1 males. For every 100 females age 18 and over, there were 84.5 males.

The median income for a household in the city was $30,417, and the median income for a family was $35,625. Males had a median income of $26,875 versus $17,333 for females. The per capita income for the city was $13,805. About 18.5% of families and 18.9% of the population were below the poverty line, including 24.0% of those under age 18 and 12.1% of those age 65 or over.