Osage, Wyoming

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Osage is a census-designated place (CDP) in Weston County, Wyoming, United States. The population was 215 at the 2000 census.

[edit] Geography

Osage is located at 43°58′59″N, 104°25′27″W (43.982948, -104.424145)^GR1.

According to the United States Census Bureau, the CDP has a total area of 5.0 km² (1.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 215 people, 101 households, and 61 families residing in the CDP. The population density was 42.8/km² (111.0/mi²). There were 124 housing units at an average density of 24.7/km² (64.0/mi²). The racial makeup of the CDP was 96.74% White, 2.79% Native American, and 0.47% from two or more races. Hispanic or Latino of any race were 0.93% of the population.

There were 101 households out of which 20.8% had children under the age of 18 living with them, 48.5% were married couples living together, 6.9% had a female householder with no husband present, and 39.6% were non-families. 34.7% of all households were made up of individuals and 14.9% had someone living alone who was 65 years of age or older. The average household size was 2.08 and the average family size was 2.62.

In the CDP the population was spread out with 19.5% under the age of 18, 7.9% from 18 to 24, 24.7% from 25 to 44, 28.8% from 45 to 64, and 19.1% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 104.8 males. For every 100 females age 18 and over, there were 119.0 males.

The median income for a household in the CDP was $25,096, and the median income for a family was $28,000. Males had a median income of $51,250 versus $20,917 for females. The per capita income for the CDP was $24,974. About 9.5% of families and 12.1% of the population were below the poverty line, including 14.7% of those under the age of eighteen and 11.1% of those sixty five or over.