Neylandville, Texas

From Wikipedia, the free encyclopedia

Neylandville is a town in Hunt County, Texas, United States. The population was 56 at the 2000 census.

[edit] Geography

Neylandville is located at 33°12′10″N, 96°0′9″W (33.202797, -96.002630)^GR1.

According to the United States Census Bureau, the town has a total area of 0.8 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 56 people, 24 households, and 15 families residing in the town. The population density was 67.6/km² (177.2/mi²). There were 32 housing units at an average density of 38.6/km² (101.2/mi²). The racial makeup of the town was 3.57% White and 96.43% African American.

There were 24 households out of which 25.0% had children under the age of 18 living with them, 41.7% were married couples living together, 8.3% had a female householder with no husband present, and 37.5% were non-families. 33.3% of all households were made up of individuals and 16.7% had someone living alone who was 65 years of age or older. The average household size was 2.33 and the average family size was 3.07.

In the town the population was spread out with 17.9% under the age of 18, 5.4% from 18 to 24, 30.4% from 25 to 44, 30.4% from 45 to 64, and 16.1% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the town was $50,417, and the median income for a family was $52,083. Males had a median income of $23,333 versus $20,417 for females. The per capita income for the town was $21,888. There were no families and 14.6% of the population living below the poverty line, including no under eighteens and 40.0% of those over 64.